Question:
Math Problem?
mubryan10
2007-03-17 09:02:57 UTC
WX+YZ=WWW
In the addition problem shown above, W, X, Y, and Z represent nonzero digits. What is the value of Y?
Four answers:
Vinny G
2007-03-17 10:10:40 UTC
If w,x,y,and z all represent digits then w has to equal 1 because you can't add 2 two digit numbers and get a number greater than 198. That makes

1X + YZ = 111

For this to work, X has to be at least 2 for YZ to be a 2 digit number. Now taking 111 - 12 all the way to 111 - 19 (111- all the numbers1X could be) this equals all numbers in the 90's.

This makes YZ = numbers from 99 to 92.

In any case Y is the first digit and is always 9.

Y = 9.
sweetieface19
2007-03-17 09:50:57 UTC
W=6, X=12, Y=36, Z=4
Gaby
2007-03-17 09:18:12 UTC
WX+YZ =WWW



You just need to reorganize the equation:

1. Move WX to the right side (by substracting)

WX(-WX)+YZ=WWW(-WX)

YZ=WWW-WX

2. Then leave Y alone moving Z to the right (by dividing)

YZ/Z=(WWW-WX)/Z



Y=(WWW-WX)/Z



This would be your answer, you can simplify it more if you want:

Y= (W/Z)*(WW-X), but that is about it.
lynn y
2007-03-17 09:13:13 UTC
Y = (www-wx)/ Z


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