I'm stuck on a math problem, can someone help?

Question

I need to solve 2z^3-5z^2+6z-15 divided by 2z-5 using the long division algorithm, but I keep getting a strange answer so I don't know if it's right.

Answer 1

I got z^2 + 3



heres what i did.

first factor out z^2 from (2z^3-5z^2)

you get this: z^2 * ( 2z-5) + 6z-15

then factor out 3 from the 2nd part

then you get this

z^2 * ( 2z-5) + 3(2z-5)



then divide by 2z-5 its clear that you can cancel them out then you get left with

z^2+3

Answer 2

Yes, i agree with Charles.

The answer is z^2 + 3.

The easiest way is to factor out so in the numerator you get

(2z - 5)(z^2 + 3)

and in the denominator you get

(2z-5)

so you can cancel out the (2z - 5)s and get z^2 + 3.

Get it?

Answer 3

.......... .........z^2.... ...+ 3

2z - 5 ) 2z^3 - 5z^2 + 6z - 15

.......... 2z^3 - 5z^2

-----------------------------

............. ...........0 + 6z - 15

.......... ......... ..... ..6z - 15

........... ............ ... ---------------

.............. .......... .......... 0



answer: z^2 + 3

Answer 4

wow, im sorry lol thats really hard. im only in freshman algebra so yeahh.