Help with Applications of Quadratic Equations?

Question

Find two consecutive integers such that the sum of their squares is 265

Smaller integer =
Larger integer =

Answer 1

11 and 12

Answer 2

Let the smaller integer be 'x'

So, the consicutive larger integer will be x+1

Its given that the sum of their squares is 265. ie,



x^2 + (x+1)^2 = 265

x^2 + x^2 + 2x + 1 = 265

2x^2 + 2x + 1 = 265

2x^2 + 2x - 264 = 0

now its in the form,

ax^2 + bx + c = 0



so, x = [-b +or- (b^2 - 4ac)^1/2]/2a

where,

a = 2

b = 2

c = -264



work it out and you will have x which is the smaller integer. So the next integer will be x+1.

Hope it helped lizzy.... :)

Answer 3

properly in fact it rather is used for multiple sciences. which includes engineering. each each now and then once you are attempting to clean up a actual international situation you wind up getting what you're finding for as a function like X^2 + 2x+a million or some thing. And the quadratic formula can clean up the two values of x. it rather is a exceptionally undemanding formula in arithmetic and interior of reason important yet undemanding. =============== And Manny is stable. on condition that a squared function has the form of a U, this formula may be utilized for looking issues that should do with arches. i won't have the ability to think of of any particular issues that used this top now yet as an engineering student it does are available in accessible on occasion. [-b +/- sqrt(b^2-4ac)]/2a the place ax^2+bx+c