need help solving this please and thanks?

Question

The height of a projectile fired vertically into the air (neglecting air resistance) at an initial velocity of 124 feet per second is a function of the time, t, and is given by the equation h(t) = 124t - 16t^2. Compute the following.

h(1)= ft
h(3)= ft
h(6)= ft
h(7)= ft

Answer 1

h(1)= 124*1 - 16*1^2 = 124 - 16 = 108 ft



h(3)= 124*3 - 16*3^2 = 372 - 144 = 228 ft



h(6)= 124*6 - 16*6^2 = 744 - 576 = 168 ft



h(7)= 124*7 - 16*7^2 = 868 - 784 = 84 ft

Answer 2

ok well they give you the function so when you see h() just plug in the number wherever you see a t in the equation (function) h(t) = 124t - 16t^2. so h() is actually h(t) where t represents time.



h(1) = 124(1) - 16(1)^2 = 108 ft

this represents the height or h of the object after 1 second.



h(3) = ft 124(3) - 16(3)^2 = 228 ft

this represents the height of the object after 3 seconds.



h(6) = ft 124(6) - 16(6)^2 = 168 ft

this represents the height of the object after 6 seconds. note how the answer is less than it was at 3 seconds. this is because the object has begun to fall.



h(7) = 124(7) - 16(7)^2 = 84 ft.

this represents the height of the object after 7 seconds. note how the answer is less than it was at 6 seconds. this is because the object is continuing to fall.





so lets recap: we have the function h(t) = 124t-16t^2 so when we see h(#) we know to take that number and insert it into the equation wherever we see t. then its just simple math!



I hope this helps!

Answer 3

change t to the the value of h(n)



So h(6) = 124(6)-16(6)^2



do the same for the other ones.

Answer 4

you will desire to "distribute" one element into the different: (2x-a million)(x+5)=0 2x(x+5) - a million(x+5) = 0 2x^2 + 10x - x - 5 = 0 2x^2 +9x - 5 = 0 (it incredibly is now in "known quadratic style") 2x^2 + 9x = 5 is a common style (there are a number of common varieties). If I have been doing this for homework, i could supply up on the favored quadratic style.